How do you solve #-2x-6<=1#?

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Answer 1 · 2016-12-10T21:24:47

#x >= -7/2#

First, we need to isolate the #x# term on one side of the inequality while keeping the inequality balanced:

#-2x - 6 + 6 <= 1 + 6#

#-2x - 0 <= 7#

#-2x <= 7#

Now we can solve for #x#. However, the rule for inequalities is if you multiply or divide by a negative number you must reverse the inequality:

#(-2x)/-2 color(red)(>=) 7/(-2)#

#x >= -7/2#