How do you solve #2x-4+7x< -6x+41#?

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Answer 1 · 2017-02-07T09:25:12

#2x-4+7x<-6x+41#

All #x# on one side numbers on another.

#2x+7x+6x<4+41#

#15x<45#

#x<45/15#

#x<3#

Answer 2 · 2018-08-06T02:50:26

#x<3#

We can combine the variables on the left to get

#9x-4<-6x+41#

Next, to get our variables on one side, we can add #6x# to both sides to get

#15x-4<41#

Next, add #4# to both sides to get

#15x<45#

Lastly, we divide both sides by #15# to get

#x<3#

Hope this helps!