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How do you solve $2x^2-8x=-8$ ?

1 Answer

May 17, 2016

$x=2$

Explanation:

If
$color(white)("XXX")2x^3-8x=-8$
then
$color(white)("XXX")x^2-4x=-4$ (after dividing by $2$ )

$color(white)("XXX")x^2-4x+4=0$ (after adding $4$ to both sides)

$color(white)("XXX")(x-2)^2=0$ (factoring)

$color(white)("XXX")(x-2)=0$ (since if $a*b=0$ then $a=0$ or $b=0$ )

$color(white)("XXX")x=2$ (after adding $2$ to both sides)

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