How do you solve 2x^2-5x=4?

1 Answer
Alan P.
May 30, 2015

2x^2-5x=4
is equivalent to
color(white)("XXXXX")2x^2-5x-4=0

For a quadratic in the general form
color(white)("XXXXX")ax^2+bx+c = 0
the solutions can be obtained using the quadratic root formula
color(white)("XXXXX")x=(-b+-sqrt(b^2-4ac))/(2a)

In this case the roots are:
color(white)("XXXXX")x = (5+-sqrt(25+32))/4

x= (5+sqrt(57))/4 or x=(5-sqrt(57))/4

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