How do you solve # 2m + 18 >12 #?
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"Question #e8eae"
First, isolate the #color(red)(m)# term on the left side of the inequality and the constants on the right side of the inequality while keeping he equation balanced:
#2color(red)(m) + 18 - color(blue)(18) > 12 - color(blue)(18)#
#2color(red)(m) + 0 > -6#
#2color(red)(m) > -6#
The next step is to solve for #m# while keeping the inequality balanced:
#(2color(red)(m))/color(blue)(2) > -6/color(blue)(2)#
#(color(blue)(cancel(color(black)(2)))color(red)(m))/cancel(color(blue)(2)) > -3#
#color(red)(m) > -3#
