How do you solve #2ln3x+1=5#?

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How do you solve #2ln3x+1=5#?

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Answer 1 · 2016-11-16T11:46:05

#x = e^2/3#

Explanation:

# " "#
#2ln3x + 1 = 5#
#" "#
#rArr 2ln3x = 5-1#
#" "#
#rArr2ln3x = 4#
#" "#
#rArrln3x = 4/2#
#" "#
#rArrln3x = 2#
#" "#
#rArre^(ln3x) = e^2#
#" "#
#rArr 3x = e^2#
#" "#
#rArrx = e^2/3#

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How do you solve #2ln3x+1=5#?

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