How do you solve $2k^2-2=144$ ?

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Answer 1 · 2016-08-03T08:50:35

$k = +-sqrt73$

Notice that all the numbers are even. The first thing to do is to divide by 2.

$k^2-1=72$

Usually in a quadratic equation, we make it equal to 0, but this is an exception because there is no $x-$ term. Change it to $x^2 = c$

$k^2 = 73$

$k = +-sqrt73$ Remember to take the positive and negative root.

How do you solve 2k^2-2=1442k^2-2=144?