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How do you solve #2e^x-1=0#?

1 Answer

Jun 11, 2018

#x= ln(1/2)#

Explanation:

#2e^x-1=0#

#2e^x=1#

#e^x=1/2#

Take natural log of both sides:
#lne^x=ln(1/2)#

#x= ln(1/2)#

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