Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you solve #25^(x-1)=125^(4x)#?

1 Answer

Aug 19, 2016

#x=-1/5#

Explanation:

Since #25=5^2# and #125=5^3# you can rewrite:

#5^(2(x-1))=5^(3(4x))#

that implies:

#2(x-1)=3(4x)#

that's

#2x-2=12x#

#10x=-2#

#x=-1/5#

Related questions

See all questions in Natural Logs

Impact of this question

4019 views around the world

You can reuse this answer
Creative Commons License