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How do you solve #25^(x-1)=125^(4x)#?

1 Answer

Aug 19, 2016

#x=-1/5#

Explanation:

Since #25=5^2# and #125=5^3# you can rewrite:

#5^(2(x-1))=5^(3(4x))#

that implies:

#2(x-1)=3(4x)#

that's

#2x-2=12x#

#10x=-2#

#x=-1/5#

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