How do you solve #21>=3(a-7)+9#?
1 Answer
Feb 13, 2017
Explanation:
distribute brackets on the right side.
#21>=3a-21+9#
#rArr21>=3a-12# add 12 to both sides.
#21+12>=3acancel(-12)cancel(+12)#
#rArr33>=3a# To solve for a, divide both sides by 3
#33/3>=(cancel(3) a)/cancel(3)#
#rArr11>=a" or "a<=11" is the solution"#
