How do you solve #20^(n-2)+6.5=87#?

1 Answer
Teddy
Jun 15, 2018

#n=(ln(80.5)+2ln(20))/ln(20)#

Explanation:

First, we subtract 6.5 from both sides to get
#20^(n-2)=80.5#
Taking the natural log (or whatever base you choose), we get
#(n-2)ln(20)=ln(80.5)#
#nln(20)-2ln(20)=ln(80.5)#
#nln(20)=ln(80.5)+2ln(20)#
#n=(ln(80.5)+2ln(20))/ln(20)#

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