How do you solve 20^(n-2)+6.5=87?

1 Answer
Jun 15, 2018

n=(ln(80.5)+2ln(20))/ln(20)

Explanation:

First, we subtract 6.5 from both sides to get
20^(n-2)=80.5
Taking the natural log (or whatever base you choose), we get
(n-2)ln(20)=ln(80.5)
nln(20)-2ln(20)=ln(80.5)
nln(20)=ln(80.5)+2ln(20)
n=(ln(80.5)+2ln(20))/ln(20)