How do you solve 2(x-2)^(2/3) = 502(x2)23=50?

1 Answer
Apr 10, 2015

If 2(x-2)^(2/3) = 502(x2)23=50
then
(x-2)^(2/3) = 25(x2)23=25

If we cube both sides we get
(x-2)^2 = 25^3 = 25^2*5^2(x2)2=253=25252

or
(x-2)^2 - 125^2 = 0(x2)21252=0

remember that anything of the form
(a^2-b^2)(a2b2) can be factored as (a-b)(a+b)(ab)(a+b)

we have
((x-2)-125)((x-2)+125) = 0((x2)125)((x2)+125)=0
or
(x-127)(x+123)=0(x127)(x+123)=0

so
x=127x=127
or
x=-123x=123