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How do you solve #2^(x-1)=23#?

1 Answer

Sep 18, 2016

#:. x~~5.5236#.

Explanation:

#2^(x-1)=23 rArr 2^x.2^-1=23 rArr 2^x=2*23=46#

Taking, #log_10# of both sides,

#log_10 2^x=log_10 46#

#:. x*log_10 2=log_10 46#.

#:. x=log_10 46/log_10 2=1.6628/0.3010~~5.5236#.

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