How do you solve $2(a-6)^2-45=53$ ?

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Answer 1 · 2016-08-18T20:34:50

$a =-1or a = 13$

This is a quadratic equation which we can solve by an easy method because there is no term in $a$ .

$2(a-6)^2 -45=53" isolate the term with the variable"$

$2(a-6)^2 =53+45$

$2(a-6)^2 = 98" isolate the factor with the variable"$

$(a-6)^2 =49" find the square root of both sides"$

$a-6 = +-7$

$a-6 = +7 rArr a = 7+6 = 13$
$a-6 = -7 rArr a = -7+6 = -1$

How do you solve 2(a-6)^2-45=532(a-6)^2-45=53?