How do you solve -2/3x-4 < -8x-223x4<8x2?

1 Answer
Apr 29, 2018

x < 3/11x<311

Explanation:

-2/3x - 4 < -8x - 223x4<8x2

First, add 44 to both sides of the inequality:
-2/3x - 4 quadcolor(red)(+quad4) < -8x - 2 quadcolor(red)(+quad4)

-2/3x < -8x + 2

Add 8x to both sides of the inequality:
-2/3x quadcolor(red)(+quad8x) < -8x + 2 quadcolor(red)(+quad8x)

7 1/3x < 2

22/3x < 2

Multiply both sides by 3:
22/3x color(red)(*quad3) < 2 color(red)(*quad3)

22/cancel(3)x cancel(color(red)(*quad3)) < 6

22x < 6

x < 6/22

Divide numerator and denominator by 2:
x < 6/22 color(red)(-: 2/2)

x < 3/11

Hope this helps!