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How do you solve #-2/3x+3<11#?

1 Answer

Mar 28, 2017

#x > -12#

Explanation:

#- 2/3 x + 3 < 11#

subtract #3# to both sides
#- 2/3 x + 3 - 3 < 11 - 3 #

#- 2/3 x < 8 #

bescause the coefficient of #x# is -ve value, change the position to become +ve value.
# -8 < 2/3 x #

multiply both sides with #3/2#
# -8 * 3/2 < 2/3 x * 3/2 #

#-12 < x# or #x > -12#

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