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How do you solve #-2.3*e^(-6m-10)=-38.8#?

1 Answer

A. S. Adikesavan

Jan 25, 2017

#m =- 1/6(10+ln(38.8/2.3))=-2.1376#, nearly.

Explanation:

Here,

#e^(-(6m+10))=38.8/2.3#. Inversely,

-#6m-10=ln(38.8/2.3)#, giving

#m= -1/6(10+ln(38.8/2.3))#

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