Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you solve #15e^-x=645#?

1 Answer

Jan 16, 2017

#x~=-3.76#

Explanation:

#e^-x=645/15=43#

We take logs of both sides:

#loge^-x=log43~=3.76#

But #loge^-x#, by definition, is the power to which we raise the base #e# to get #e^-x#, so here #-x~=3.76#.

And #x~=-3.76#

Related questions

See all questions in Natural Logs

Impact of this question

1581 views around the world

You can reuse this answer
Creative Commons License