How do you solve $- 14 < - 7 (3 x + 2)$ $-14< - 7( 3x + 2)$ ?

Question

How do you solve $- 14 < - 7 (3 x + 2)$ $-14< - 7( 3x + 2)$ ?

1 Answer

Impact of this question

1587 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-19T12:31:38

$x < 0$ $x<0$

Explanation:

$distribute the bracket$ $"distribute the bracket"$

$- 14 < - 21 x - 14$ $-14<-21x-14$

$add 21x to both sides$ $"add 21x to both sides"$

$21x-14 < cancel(-21x)cancel(+21x)-14$

$rArr21x-14 < -14$

$"add 14 to both sides"$

$21xcancel(-14)cancel(+14) < cancel(-14)cancel(+14)$

$rArr21x < 0rArrx<0$

Science

Math

Humanities

... and beyond

How do you solve $- 14 < - 7 (3 x + 2)$ $-14< - 7( 3x + 2)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you solve -14< - 7( 3x + 2)−14<−7(3x+2)-14< - 7( 3x + 2)?

1 Answer

Explanation:

Related questions

Impact of this question

How do you solve $- 14 < - 7 (3 x + 2)$ $-14< - 7( 3x + 2)$ ?