How do you solve #13-4x < 25#?

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Answer 1 · 2018-07-24T19:06:08

#x > -3#

#13 - 4x < 25#

Add #color(blue)(4x)# to both sides:
#13 - 4x quadcolor(blue)(+quad4x) < 25 quadcolor(blue)(+quad4x)#

#13< 25 + 4x#

Subtract #color(blue)25# from both sides:
#13 quadcolor(blue)(-quad25) < 25 + 4x quadcolor(blue)(-quad25)#

#-12 < 4x#

Divide both sides by #color(blue)4#:
#(-12)/color(blue)4 < (4x)/color(blue)4#

#-3 < x#

Therefore,
#x > -3#

Here's a graph of it on a number line:
enter image source here

The open circle on #-3# means that it is not a solution (but anything greater than it is).

Hope this helps!