How do you solve #12h+30<10h-45#?

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Answer 1 · 2017-07-11T02:39:02

Solve as you would an equation, but with the inequality in place of the equal symbol.

#h=-75/2#

Solve:

#12h+30<10h-45#

Subtract #30# from both sides.

#12h+color(red)cancel(color(black)(30))-color(red)cancel(color(black)(30))<10h-45-30#

Simplify.

#12h<10h-75#

Subtract #10h# from both sides.

#12h-10h< color(red)cancel(color(black)(10h))-color(red)cancel(color(black)(10h))-75#

Simplify.

#2h<-75#

Divide both sides by #2#.

#(color(red)cancel(color(black)(2))h)/color(red)cancel(color(black)(2))<-75/2#

Simplify.

#h<-75/2#