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How do you solve # -12<6+2a<8 #?

1 Answer

Jul 4, 2016

#-9 < a < 1.#

Explanation:

Given that #-12<6+2a<8#

Adding #-6#, #-12-6<-6+6+2a<-6+8,# i.e., #-18<2a<2.#

Now we multiply the inequality by#1/2,# noting that #1/2# being #+ve#, its order will not be changed.

Hence, #-18*1/2<2a*1/2<2*1/2, rArr -9 < a < 1.#,

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