# How do you solve 10x+43<13?

May 7, 2015

The answer is $x < - 3$ .

Solve $10 x + 43 < 13$ .

Isolate the $x$ term on one side by subtracting 43 from both sides.

$10 x + 43 - 43 < 13 - 43$ =

$10 x < - 30$

Divide both sides by $10$.

$\frac{10 x}{10} < - \frac{30}{10}$ =

$x < - 3$