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How do you solve #10^(2x)+3=8#?

1 Answer

Jul 9, 2016

#10^(2x)+3=8#

#10^(2x)=5#

#2x * log(10) = log(5)#

#2x = log(5) / log(10)#

#x = (log(5) / log(10)) * 1/2#

#x = log(5) / (2 log(10))#

Explanation:

Remember that #log_b (x^r) = r log_b (x)#.

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