How do you sketch one cycle of $y=cotx$ ?

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Answer 1 · 2016-11-20T03:30:08

Graph is inserted. See explanation.

The period ( cycle ) of cot x is $pi$ .

In one cycle $x in (0, pi)$ ,

the ends $x= 0 and x = 0 and x = pi$ are points if infinite

discontinuity. The midpoint is $(pi/2, 0)$

In the inserted graph, look for $x in (3.14, 0)$ , for one cycle..

graph{cotx [-5, 5, -2.5, 2.5]}

How do you sketch one cycle of y=cotxy=cotx?