How do you simplify $(x^{2} + 12 x + 11) \cdot \frac{x + 9}{x^{2} + 20 x + 99}$ $(x^2+12x+11) * (x+9) /( x^2+20x+99)$ ?

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Answer 1 · 2015-07-22T11:55:18

Factor and cancel identical terms in the numerator and denominator to get $x + 1$ $x+1$

$(x^{2} + 12 x + 11) \cdot \frac{x + 9}{x^{2} + 20 x + 99}$ $(color(red)(x^2+12x+11))⋅(color(blue)(x+9))/(color(green)(x^2+20x+99))$

$= \frac{(x + 1) (x + 11) (x + 9)}{(x + 9) (x + 11)}$ $= (color(red)((x+1)(x+11))color(blue)((x+9))) / (color(green)((x+9)(x+11))$

$= (color(red)((x+1)cancel((x+11)))color(blue)(cancel((x+9)))) / (color(green)(cancel((x+9))cancel((x+11)))$

$=x+1$

How do you simplify (x^2+12x+11) * (x+9) /( x^2+20x+99)(x2+12x+11)⋅x+9x2+20x+99(x^2+12x+11) * (x+9) /( x^2+20x+99)?