How do you multiply $\frac{5x^2+16x+3}{36x^2-25} \cdot (6x^2+5x)$ ?

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Answer 1 · 2018-05-26T18:23:44

$(x*(5*x^2+16x+3))/(6x-5)$

The numerator is given by
$36x^2-25=(6x-5)(6x+5)$
and the factor
$6x^2+5x=x(6x+5)$
So we get by cancelling
$6x+5$
the result
$(x(5x^2+16x+3))/(6x-5)$

How do you multiply \frac{5x^2+16x+3}{36x^2-25} \cdot (6x^2+5x)\frac{5x^2+16x+3}{36x^2-25} \cdot (6x^2+5x)?