How do you simplify $\sqrt{72} \cdot \sqrt{32}$ $sqrt72 * sqrt32$ ?

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How do you simplify $\sqrt{72} \cdot \sqrt{32}$ $sqrt72 * sqrt32$ ?

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Answer 1 · 2018-03-02T20:08:39

The answer is $48$ $48$

Explanation:

To multiply square roots, it is easiest to just multiply the radicands (the numbers under the radical sign) and imagine the radical signs away for a minute.
So when we see:
$\sqrt{75} \times \sqrt{32}$ $sqrt75 xx sqrt32$ mentally remove the radicands and multiply.
$72 \times 32 = 2, 304$ $72 xx 32 = 2,304$

Now, we're going to put the radical sign back on and find the square root:
$\sqrt{2304} = 48$ $sqrt2304 = 48$

Answer 2 · 2018-03-02T20:10:57

$48$ $48$

Explanation:

$\sqrt{72} \times \sqrt{32}$ $sqrt72xxsqrt32$

$\sqrt{72} = \sqrt{2 \times 2 \times 2 \times 3 \times 3}$ $sqrt72=sqrt(2xx2xx2xx3xx3)$

$\sqrt{32} = \sqrt{2 \times 2 \times 2 \times 2 \times 2}$ $sqrt32=sqrt(2xx2xx2xx2xx2)$

Therefore,

$\sqrt{72} \times \sqrt{32} = \sqrt{2 \times 2 \times 2 \times 3 \times 3} \times \sqrt{2 \times 2 \times 2 \times 2 \times 2}$ $sqrt72xxsqrt32=sqrt(2xx2xx2xx3xx3)xxsqrt(2xx2xx2xx2xx2)$

$= 2 \times 3 \times \sqrt{2} \times 2 \times 2 \times \sqrt{2}$ $= 2xx3xxsqrt2xx2xx2xxsqrt2$

$= 2 \times 3 \times 2 \times 2 \times 2$ $= 2xx3xx2xx2xx2$

$= 48$ $= 48$

~Hope this helps! :)

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How do you simplify $\sqrt{72} \cdot \sqrt{32}$ $sqrt72 * sqrt32$ ?

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