How do you multiply $sqrt[27b] * sqrt[3b^2L]$ ?

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Answer 1 · 2017-06-25T16:17:44

$sqrt(27b)*sqrt(3b^2L)=9bsqrt(bL)$

As $sqrta*sqrtb=sqrt(axxb)$

Therefore $sqrt(27b)*sqrt(3b^2L)$

= $sqrt(27bxx3b^2L)$

= $sqrt(3xx3xx3xxcolor(red)(bxx3)xxbxxbxxL)$

= $sqrt(3xx3xx3xxcolor(red)(3xxb)xxbxxbxxL)$

= $sqrt(ul(3xx3)xxul(3xx3)xxul(bxxb)xxbxxL)$

= $3xx3xxbxxsqrt(bL)$

= $9bsqrt(bL)$

Answer 2 · 2017-06-25T16:31:20

$color(blue)(9bsqrt(bL)$

$sqrt(27b)*sqrt(3b^2L)$

$:.=sqrt(3*3*3b)*sqrt(3b^2L)$

$:.=3sqrt(3b)*sqrt(3b^2L)$

$:.=3sqrt(3b)*bsqrt(3L)$

$:.=3bsqrt(3b3L)$

$:.=3*3bsqrt(bL)$

$:.color(blue)(=9bsqrt(bL)$

How do you multiply sqrt[27b] * sqrt[3b^2L]sqrt[27b] * sqrt[3b^2L]?