How do you simplify sqrt ((4a^3 )/( 27b^3))4a327b3?

2 Answers
Jun 9, 2016

sqrt((4a^3)/(27b^3))=(2a)/(3b)sqrt(a/(3b))4a327b3=2a3ba3b

Explanation:

sqrt((4a^3)/(27b^3))4a327b3

= sqrt((2xx2xxaxxaxxa)/(3xx3xx3xxbxxbxxb))2×2×a×a×a3×3×3×b×b×b

= sqrt((ul(2xx2)xxul(axxa)xxa)/(ul(3xx3)xx3xxul(bxxb)xxb))

= (2a)/(3b)sqrt(a/(3xxb))

= (2a)/(3b)sqrt(a/(3b))

Jun 10, 2016

Just another way of writing the same thing as the other solution:

" "color(green)((2asqrt(3ab))/(3b^2))

Explanation:

Given:" "sqrt((4a^3)/(27b^3))

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
color(blue)("Concept of approach")

You look for numbers that are squared. Take them outside the square root and 'get rid' of the square.

Example: Suppose we had sqrt(12)

Choosing the factors of 3xx4=12 we write it as:

sqrt(3xx4) but 4 is 2^2 giving sqrt(3xx2^2)

Take the 2 out side the square root giving

" "2sqrt(3)
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
color(blue)("Solving your question")

color(brown)("Mathematicians do not like square roots in the denominator so we will 'get rid' of it")color(brown)("later.")

" Write as: "(sqrt(4a^3))/(sqrt(27b^3))
'.......................................................................................
we know that
27" "=" "3xx9" " =" "3xx3^2" and "b^3" "=" "b^2xxb
4" "=2^2" and " a^3" "=a^2xxa
'.........................................................................................

" Write as "sqrt(2^2xxa^2xxa)/sqrt(3^2xx3xxb^2xxb)

Take the squared values outside the square roots giving

" "color(blue)((2a sqrt(a))/(3bsqrt(3b)))
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
color(blue)("Now to 'get rid' of the square root in the denominator")

Multiply by 1 and you do not change the value or how it looks.
1 can come in many forms: 1/1"; "(-1)/(-1)"; "2/2"; "sqrt(3b)/sqrt(3b)

So we can multiply by 1 and not change the inherent value but we can change the way it looks.

color(brown)("Multiply by 1 but in the form of "1=sqrt(3b)/sqrt(3b))

(2a sqrt(a))/(3bsqrt(3b))xxsqrt(3b)/sqrt(3b)" "=" "(2asqrt(a)sqrt(3b))/(3bsqrt(3b)sqrt(3b))

But sqrt(3b)xxsqrt(3b)=3b giving:

(2asqrt(a)sqrt(3b))/(3bxxb)" "=" "(2asqrt(a)sqrt(3b))/(3b^2)

But sqrt(a)sqrt(3b) = sqrt(3ab)

color(brown)("If you can take things out of square roots you can put things back in!")

" "color(green)((2asqrt(3ab))/(3b^2))