How do you simplify $\sqrt{27} + 2 \sqrt{3} - \sqrt{12}$ $sqrt27+2sqrt3-sqrt12$ ?

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Answer 1 · 2017-07-17T14:10:10

$\sqrt{27} + 2 \sqrt{3} - \sqrt{12} = 3 \sqrt{3}$ $sqrt27+2sqrt3-sqrt12=3sqrt3$

$\sqrt{27} + 2 \sqrt{3} - \sqrt{12}$ $sqrt27+2sqrt3-sqrt12$

= $\sqrt{3 \times 3 \times 3} + 2 \sqrt{3} - \sqrt{2 \times 2 \times 3}$ $sqrt(3xx3xx3)+2sqrt3-sqrt(2xx2xx3)$

= $sqrt(ul(3xx3)xx3)+2sqrt3-sqrt(ul(2xx2)xx3)$

= $3sqrt3+2sqrt3-2sqrt3$

= $3sqrt3$

How do you simplify sqrt27+2sqrt3-sqrt12√27+2√3−√12sqrt27+2sqrt3-sqrt12?