How do you simplify $\sqrt{x^{3} y^{4}}$ $sqrt(x^3y^4)$ ?

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Answer 1 · 2015-04-07T17:26:24

Re-write the arguments of square root as much as possible into a product of squares, then extract the squares from inside the root.

$\sqrt{x^{3} y^{4}} = \sqrt{x^{2} \cdot x \cdot {(y^{2})}^{2}}$ $sqrt(x^3y^4) = sqrt(x^2*x*(y^2)^2)$

$= x y^{2} \sqrt{x}$ $= xy^2sqrt(x)$

How do you simplify sqrt(x^3y^4)√x3y4sqrt(x^3y^4)?