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How do you simplify #sqrt(36x^3)#?

1 Answer

Mar 24, 2015

Extract the largest squares from the terms of the square root argument and remove them from within the square root.

#36 = 6^2#
#x^3 = (x^2) (x)#

So
#sqrt(36x^3)#
# = sqrt(6^2*x^2*x)#
# = sqrt(6^2)*sqrt(x^2)*sqrt(x)#
#= 6x sqrt(x)#

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