How do you simplify #sqrt(108x^6y^4z^5)#?

1 Answer
Shwetank Mauria
May 29, 2017

#sqrt(108x^6y^4z^5)=6x^3y^2z^2sqrt(3z)#

Explanation:

#sqrt(108x^6y^4z^5)#

= #sqrt(2xx2xx3xx3xx3xx x xx x xx x xx x xx x xx x xxyxxyxxyxxyxxzxxzxxzxxzxxz)#

= #sqrt(ul(2xx2)xxul(3xx3)xx3xx ul(x xx x) xx ul(x xx x) xx ul(x xx x) xxul(yxxy)xxul(yxxy)xxul(zxxz)xxul(zxxz)xxz)#

= #2xx3xx x xx x xx x xxyxxyxxzxxz xxsqrt(3xxz)#

= #6x^3y^2z^2sqrt(3z)#

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