How do you simplify #root8((a^16)^-5)#?

1 Answer
EZ as pi
Jul 6, 2016

#1/a^10#

Explanation:

Let's start under the root and remove the bracket by multiplying the indices (power to a power law)

#root(8)(a^-80)#

A negative index can be made positive by taking the reciprocal.

Now we have: #1/(root(8)(a^80))#

Find a root by dividing the index by the root

#1/a^10#

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