How do you simplify $ln (x + 3) + ln (e - 3) = ln 16$ $ln(x+3)+ln(e-3)=ln 16$ ?

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Answer 1 · 2016-05-14T04:56:27

$x = \frac{16}{e - 3} - 3 = - 56.79, \neq a r l y$ $x=16/(e-3) - 3=-56.79, nearly$

Use log a + log b = log (ab).

Here, ln(x+3)(e-3)=ln 16.

log is single-valued.

So, (x+3)(e-3) = 16. Solve for x.

Answer: $x = \frac{16}{e - 3} - 3$ $x=16/(e-3) - 3$ .

How do you simplify ln(x+3)+ln(e−3)=ln16ln(x+3)+ln(e-3)=ln 16?