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How do you simplify #ln(3x^2-9x)+ln(1/(3x))#?

1 Answer

A. S. Adikesavan

May 3, 2016

#log (x-3)#, x > 3.

Explanation:

Use log #abc = log a + log b + log c and log(1/d) = - log d#,

#log (3x^2-9x)+log(1/(3x))#

#=log((3)(x)(x-3))-log( (3)(x))#

#=log 3+log x + log(x-3)-log 3 - log x#

#=log (x-3)#, with x > 3..

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