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How do you simplify #e^(ln sqrtx)#?

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1 Answer

Shwetank Mauria

Oct 24, 2016

#e^(lnsqrtx)=sqrtx#

Explanation:

Let #e^(lnsqrtx)=u#,

then #lnsqrtx=lnu#

Hence #u=sqrtx#

i.e. #e^(lnsqrtx)=sqrtx#

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