How do you simplify #e^(3lnx - 2lny)#?

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Answer 1 · 2016-06-28T11:56:48

#x^3/y^2#.

Use #ln a^n=n ln a, lnb-ln c= ln (b/c) and e^ln d=d#.

Here,

#e^(3 ln x-2 ln y)#

#=e^(lnx^3-lny^2)#

#=e^ln(x^3/y^2)=x^3/y^2#.

How do you simplify #e^(3*ln*x - 2*ln*y)#?