# How do you simplify (e^-3 * e^4)/(e^-2 * e^-1)?

Mar 4, 2016

$\frac{{e}^{- 3} \cdot {e}^{4}}{{e}^{- 2} \cdot {e}^{- 1}} = {e}^{3}$

#### Explanation:

From laws of exponents, ${x}^{- n} = \frac{1}{x} ^ n$ and ${x}^{m} \cdot {x}^{n} = {x}^{m + n}$.

Hence, to convert a negative exponent into a positive one, we may take it to the top or bottom of the fraction.

$\therefore \frac{{e}^{- 3} \cdot {e}^{4}}{{e}^{- 2} \cdot {e}^{- 1}} = \frac{{e}^{2} \cdot {e}^{4} \cdot {e}^{1}}{{e}^{4}}$

$= {e}^{7} / {e}^{4}$

$= {e}^{3}$