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How do you simplify #cos^2B / (1-sinB)#?

1 Answer

Oct 24, 2015

#(cos^2(B))/(1-sin(B)) = 1+sin(B)#

Explanation:

Based on the definitions of #sin# and #cos# and on the Pythagorean Theorem
#color(white)("XXX")cos^2(B)+sin^2(B) = 1#
or
#color(white)("XXX")cos^2(B) = 1-sin^2(B)#

#color(white)("XXXXXXX")=(1-sin(B))*(1+sin(B))#

Therefore
#color(white)("XXX")(cos^2(B))/(1-sin(B)) = (cancel((1-sin(B)))*(1+sin(B)))/(cancel((1-sin(B)))#

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