How do you simplify and find the restrictions for #(6)/(x+3)#?

1 Answer
Anthony R.
Apr 25, 2017

See explanation

Explanation:

The function #6/(x+3)# will have a restricted domain at #x=-3#.

We know this because the denominator of our function cannot be #0# and to find what value this occurs, we set the denominator equal to #0# such that:

#x+3=0 -> x=-3#

What this tells us that the graph will have a vertical asymptote at #x=-3#

Thus our domain for this function is: #{x| x!= -3} or (-oo,-3) uu (-3,oo)#

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