How do you find the excluded values of $\frac{2x+1}{x^2-x-6}$ ?

Question

11361 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2014-11-23T15:21:38

Since denominators cannot be zero, we have

$x^2-x-6 ne 0$

by factoring out,

$(x+2)(x-3) ne 0 => x ne -2, 3$

Hence, $x=-2$ and $x=3$ are its excluded values.

I hope that this was helpful.

How do you find the excluded values of \frac{2x+1}{x^2-x-6}\frac{2x+1}{x^2-x-6}?