How do you simplify the expression and find the excluded values for the rational expression $\frac{4x-2}{2x^2+x-1}$ ?

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Answer 1 · 2014-12-14T15:44:09

Since the denominator cannot be zero,

$2x^2+x-1=(2x-1)(x+1) ne 0$

$=> {(2x-1 ne 0 => 2x ne 1 => x ne 1/2),(x+1 ne 0 => x ne -1):}$

Hence, the excluded values are $1/2$ and $-1$ .

I hope that this was helpful.

How do you simplify the expression and find the excluded values for the rational expression \frac{4x-2}{2x^2+x-1}\frac{4x-2}{2x^2+x-1}?