How do you simplify and divide #(28c^3d-42cd^2+56cd^3)div(14cd)#?

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Answer 1 · 2016-10-04T21:02:04

#2c^2-3d+4d^2#

#(28c^3d-42cd^2+56cd^3)/(14cd)#

There are 2 methods:

#1. rarr# factor the numerator and cancel

#(cancel(14cd)(2c^2-3d+4d^2))/cancel(14cd)#

=#2c^2-3d+4d^2#

#2. rarr# make 3 separate fractions and simplify each

=#(28c^3d)/(14cd) -(42cd^2)/(14cd) +(56cd^3)/(14cd)#

=#2c^2-3d+4d^2#