How do you evaluate $(a+3b)/(4c)$ when $a = 4, b = - 2, and c = - 3$ ?

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Answer 1 · 2017-08-30T17:27:55

$1/6$

Replace each variable by the value given.

$color(blue)(a = 4)" "color(red)(b = -2)" "color(forestgreen)(c =-3)$

$(color(blue)(a)+3color(red)(b))/(4color(forestgreen)(c))$

$=(color(blue)(4)+3color(red)((-2)))/(4color(forestgreen)((-3)))" "larr$ multiply by the brackets

$=(color(blue)(4)color(red)(-6))/(color(forestgreen)(-12))$

$= (-2)/12$

$=1/6$

How do you evaluate (a+3b)/(4c)(a+3b)/(4c) when a = 4, b = - 2, and c = - 3a = 4, b = - 2, and c = - 3?