How do you simplify (-7c)/(21c^2-35c)−7c21c2−35c?

2 Answers
Jim G.
Sep 25, 2016

-1/(3c-5)−13c−5

Explanation:

When dealing with algebraic fractions the first step is to factorise the numerator/denominator, if possible.

Here, the denominator has a color(blue)"common factor"common factor of 7c which can be taken out.

rArr(-7c)/(7c(3c-5))⇒−7c7c(3c−5)

Now cancel, common factors on numerator/denominator.

rArr(-cancel(7c)^1)/(cancel(7c)^1(3c-5))

=-1/(3c-5)

EZ as pi
Sep 25, 2016

1/(5-3c)

Explanation:

With algebraic fractions, check first if they can be factored,

(-7c)/(21c^2-35c) = " " (-7c)/(7c(3c-5))" "larr with factors - cancel!

=(-cancel(7c))/(cancel(7c)(3c-5)) " "larr the minus sign can be anywhere ...

= (color(red)(-)1)/(3c-5) = color(red)(-)1/(3c-5) = 1/(color(red)(-)(3c-5)

=1/(5-3c)" "larr note the switch-round

Related questions
See all questions in Division of Polynomials
Impact of this question
2198 views around the world
You can reuse this answer
Creative Commons License