How do you divide 9x^2-16 by 3x+4?
1 Answer
Nov 4, 2014
Treat your terms of your dividends like digits... However, you also need to consider "missing" terms (in the case of
For your divisor, you need only divide using the first term
3x - 4
____________
(3x + 4) / (9x^2 + 0x - 16)
- (9x^2 + 12x)
- 12x - 16
- (- 12x - 16)
0
