How do you simplify $(6y^2 + 18y)/( 2y^3 - 6y^2 - 36y )$ ?

Question

1823 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-10-07T16:18:26

$3/(y-6)$

$(6y^2 + 18y)/(2y^3 - 6y^2 - 36y)$

$(6cancel(y) (y+3))/(2cancel(y) * (y^2 - 3y - 18)) = (3(y+3))/(y^2 - 3y - 18)$

You can write the denominator as

$y^2 - 3y - 18 = y^2 - 6y + 3y - 18$

$y * (y + 3) - 6(y+3) = (y+3) * (y-6)$

The expression will thus be

$(3 * cancel(y+3))/(cancel(y+3) * (y-6)) = 3/(y-6)$

How do you simplify (6y^2 + 18y)/( 2y^3 - 6y^2 - 36y )(6y^2 + 18y)/( 2y^3 - 6y^2 - 36y )?