How do you simplify (6y^2 + 18y)/( 2y^3 - 6y^2 - 36y )6y2+18y2y3−6y2−36y?

1 Answer
Stefan V.
Oct 7, 2015

3/(y-6)3y−6

Explanation:

(6y^2 + 18y)/(2y^3 - 6y^2 - 36y)6y2+18y2y3−6y2−36y

(6cancel(y) (y+3))/(2cancel(y) * (y^2 - 3y - 18)) = (3(y+3))/(y^2 - 3y - 18)

You can write the denominator as

y^2 - 3y - 18 = y^2 - 6y + 3y - 18

y * (y + 3) - 6(y+3) = (y+3) * (y-6)

The expression will thus be

(3 * cancel(y+3))/(cancel(y+3) * (y-6)) = 3/(y-6)

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