How do you simplify $64^{- \frac{1}{2}}$ $64^(-1/2)$ ?

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Answer 1 · 2017-01-25T19:54:54

See explanation.

$64^{- \frac{1}{2}} = \frac{1}{64^{\frac{1}{2}}} = \frac{1}{\sqrt{64}} = \frac{1}{8}$ $64^(-1/2)=1/64^(1/2)=1/sqrt(64)=1/8$

In the calculations I used:

$a^{- b} = \frac{1}{a^{b}}$ $a^-b=1/a^b$

and